Given the following quadratic equation y = (x-3)^(2) + 9 What would be the vertex (h,k)? Vetex = (_,_)

Question

Given the following quadratic equation
`y = (x-3)^(2) + 9`

What would be the vertex (h,k)?

Vetex = (_,_)

Answer 1

Answer:
`h=3\\k=9`

Explanation:

By definition, we know that the quadratic equation in the vertex form is:

`y=a(x-h)^(2)+k`

Where (h, k) is the vertex.

We have the equation given in the problem:

`y=(x-3)^(2)+9`

Therefore, you can conclude that the vertex is (3,9).

Therefore the answer is:

`h=3\\k=9`

Answer 2

Vertex = (3, 9)

Explanation:

The vertex form of a quadratic equation y = a(x - h)^2 + k

Now let's compare the vertex form with the given equation and find the vertex = (h, k)

Vertex = (3, 9)

THank you.