Question

What is the molecular formula of the compound with a molecular weight of 112 g/mol and percent composition: 85.6% C and 14.4% H?

Select one:
a.C2H4
b.CH2
c.C4H8
d.C8H16

Answer 1

Step-by-step explanation:

Mass of C = 112g * (85.6/100) = 95.87g

Moles of C = 95.87g / (12g/mol) = 8

Mass of H = 112g * (14.4/100) = 16.13g

Moles of C = 16.13g / (1g/mol) = 16

Hence the compound is C8H16. (D)