In which direction does the right side of this graph point? F(x)=3x^4-x^2+4x-2

Question

asked Sep 5, 2020 181 views

2 Answers

Peter Henry · Answer 1 · 2020-09-10T14:37:23+0000

Answer:

Positive direction (Up)
$\uparrow$

Explanation:

The given function is

f(x)=3x^4-x^2+4x-2

The degree of this polynomial is even.

The leading coefficient is positive 3.

The polynomial will rise
$\uparrow$ on the left and rise
$\uparrow$ on the right.

Therefore the right side of the graph of
f(x)=3x^4-x^2+4x-2 points in the positive direction of the y-axis.