Question

My calculator wasn’t working for this I’m not sure how to solve it but help would be coolio

Answer 1

We know that:

`_nP_k = (n!)/((n-k)!)`

so in this case
`n = 5`,
`k=3` and:

`_5P_3=(5!)/((5-3)!)=(5!)/(2!)=(5\cdot4\cdot3\cdot2\cdot1)/(2\cdot1)=(120)/(2)=\boxed{60}`