Question

The midpoint of EF is point P at (−6,−2). If point E is at (2,−4), what are the coordinates of point F?

A) (−14,0)
B) (−10,−8)
C) (−5,3)
D) (−2,−3)

Answer 1

a. (-14, 0)

Explanation:

Answer 2

Option A is correct answer.

Explanation:

Midpoint formula is given by

x =
`(x_(1) +x_(2))/(2)`

y =
`(y_(1) +y_(2))/(2)`

Here E = (2,-4)

so x1 = 2 and y1= -4

x = -6 and y = -2 are given

therefore using above mid point formula

-6 =
`(2 +x_(2))/(2)`

-6X2 = 2+x2

-12 = 2+x2

x2 = -12-2 = -14

Likewise

-2 =
`(y_(1) +y_(2))/(2)`

-2X2 = -4 +y2

-4 = -4 +y2

y2 = 0

therefore Coordinate for point F will be (-14,0)