asked 95.7k views
2 votes
If 0° ≤ θ ≤ 90° and cosθ =
11
15
, what is the value of sin (90° - θ)?

2 Answers

2 votes

cos Ф = 11/5. Calculate the value of angle Ф:

cos⁻¹(11/15) = 42.83342807°

sin(90-Ф) =sin (90-42.83342807) = sin(47.16657193) = 11/5

So cos Ф = sin(90-Ф) = 11/15

answered
User Denim
by
8.4k points
5 votes

Answer:


sin (90 - \theta) \approx 0.73

Explanation:

The given expression is


cos\theta =(11)/(15)

According to trigonometric identities


sin(90-\theta)=cos\theta

We also can find the angle using the given expression and then replace it in the sin expression


cos\theta=(11)/(15)\\ \theta=cos^(-1)((11)/(15))\approx 42.83

Now, we find the answer for the sin expression:


sin (90 - \theta)=sin(90-42.83)=sin(47.17)\approx0.73

Again, the faster way to solve this is by using the identity:

If
sin(90-\theta)=cos\theta and
cos\theta =(11)/(15), then
sin(90-\theta)=(11)/(15)

answered
User LiranNis
by
8.0k points
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