Question

If p(x) = x2 – 1 and q(x)=5(x-1), which expression is equivalent to (p – q)(x)? 5(x – 1) – x2 – 1 (5x – 1) – (x2 – 1) (x2 – 1) – 5(x – 1) (x2 – 1) – 5x – 1

Answer 1

(x^2 – 1) – 5(x – 1)

Explanation:

p(x) = x^2 – 1 and q(x)=5(x-1)

(p – q)(x) = x^2 – 1 -5(x-1)

Distribute

= x^2 - 1 -5x +5

= x^2 -5x +4