Question

Find the vertex of y=x^2+6x-16​

Answer 1

(-3,-25)

Explanation:

x^2+6x-16

=(x^2+6x+9)-16-9

=(x+3)^2-25

When a quadratic is written in the form y = a(x–h)^2 + k, the vertex is (h,k).

Vertex=(-3,-25)