Use the data in the table to answer the question. Citations are "speeding tickets." You may fill in the table to help you answer the question. Original data Line of &q…

Question

Use the data in the table to answer the question. Citations are "speeding tickets." You may fill in the table to help you answer the question.

Original data Line of "best guess" Line of best fit
Mph greater than speed limit Number of citations Outputs Residuals Outputs Residuals
5 3
7.5 6
10 10
15 5
20 6
Find the linear approximation of the data that passes through the points (5, 3) and (20, 6).

y = 15x + 9
y = 15x + 3

Answer 1

the answer is y=1/5x+2

Explanation:

Answer 2

`y=(1)/(5)x+2`

Explanation:

Given : (5, 3) and (20, 6).

To Find: the linear approximation of the data that passes through the points (5, 3) and (20, 6).

Solution:

We are given the two points (5, 3) and (20, 6).

Now to find equation of line we will use two point slope form.

Formula :
`y-y_1=(y_2-y_1)/(x_2-x_1)(x-x_1)`

`(x_1,y_1)=(5,3)`

`(x_2,y_2)=(20,6)`

Substitute the values in the formula .

`y-3=(6-3)/(20-5)(x-5)`

`y-3=(3)/(15)(x-5)`

`y-3=(1)/(5)(x-5)`

`y-3=(1)/(5)x-1`

`y=(1)/(5)x-1+3`

`y=(1)/(5)x+2`

Hence the linear approximation of the data that passes through the points (5, 3) and (20, 6) is
`y=(1)/(5)x+2`