Question

Calculate the average travel time for each distance, and then use the results to calculate.

The average time that it takes for the car to travel the first 0.25m is ___

s.


The average time to travel just between 0.25 m and 0.50 m is ____

s.


Given the time taken to travel the second 0.25 m section, the velocity would be ___

m/s.

Answer 1

The average time that it takes for the car to travel the first 0.25m is

2.23 s.

The average time to travel just between 0.25 m and 0.50 m is

0.90 s.

Given the time taken to travel the second 0.25 m section, the velocity would be

0.28 m/s.

Step-by-step explanation:

Just did this problem! :)

Answer 2

The average time that it takes for the car to travel the first 0.25m is 2.23 s

The average time that it takes for the car to travel the first 0.25 m is given by:

`t=(2.24 s+2.21 s+2.23 s)/(3)=2.227 s \sim 2.23 s`

The average time to travel just between 0.25 m and 0.50 m is 0.90 s

First of all, we need to calculate the time the car takes in each trial to travel between 0.25 m and 0.50 m:

`t_1 = 3.16 s - 2.24 s=0.92 s\\t_2 = 3.08 s- 2.21 s=0.87 s\\t_3 =3.15 s- 2.23 s=0.92 s`

Then, the average time can be calculated as

`t=(0.92 s+0.87 s+0.92 s)/(3)=0.90 s`

Given the time taken to travel the second 0.25 m section, the velocity would be 0.28 m/s

The velocity of the car while travelling the second 0.25 m section is equal to the distance covered (0.25 m) divided by the average time (0.90 s):

`v=(d)/(t)=(0.25 m)/(0.90 s)=0.28 m/s`