Question

Using the quadratic formula to solve 4x2 – 3x + 9 = 2x + 1, what are the values of x?

Answer 1

Choice c is the answer.

Explanation:

We have given a quadratic equation.

4x²-3x+9 = 2x+1

We have to solve above equation using quadratic formula.

First , Add -2x-1 into both sides of given equation, we have

4x²-3x+9 -2x-1 = 2x+1 -2x-1

Adding like terms, we have

4x²-5x+8 = 0 is general form of quadratic equation, where a = 4, b = -5 and c= 8.

x = (-b±√b²-4ac) / 2a is quadratic formula.

Putting given values in above equation, we have

x = (-(-5)±√(-5)²-4(4)(8) ) / 2(4)

x = (5±√24-128) / 8

x = (5±√-103) / 8

x = (5±√103√-1) / 8 ∴√-1 = i

x = (5±√103i) / 8 Which is the answer.

Answer 2

The value of x is:

`x=(5\pm √(103)i)/(8)`

Explanation:

we have to use the quadratic formula to solve for x.

The equation is given as:

`4x^2-3x+9=2x+1`

which could also be written as:

`4x^2-3x+9-2x-1=0\\\\4x^2-3x-2x+9-1=0\\\\\\4x^2-5x+8=0`

The quadratic formula for the quadratic equation of the type:

`ax^2+bx+c=0` is given as:

`x=(-b\pm √(b^2-4ac))/(2a)`

Here we have:

a=4, b=-5 and c=8.

Hence, by the quadratic formula we have:

`x=(-(-5)\pm √((-5)^2-4* 8* 4))/(2* 4)\\\\x=(5\pm √(25-128))/(8)\\\\\\x=(5\pm √(103)i)/(8)`

Hence, the value of x is:

`x=(5\pm √(103)i)/(8)`