Question

What is the equation of a line, in general form, that passes though points (-1,2) and (5,2)?

A.y-2=0
B.x-2=0
C.y-x-2=0

Answer 1

A

Explanation:

To write the equation of the line. first calculate the slope using the slope formula.

`m = (y_2-y_1)/(x_2-x_1) = (2-2)/(5--1)= (0)/(6) = 0`

Since the slope of this line is 0, it is horizontal and has the form y=b where b is the y-coordinate. So y = 2 is the equation. In general form, it would be y-2 = 0