Consider the graph of the linear function h(x) = –6 + x. Which quadrant will the graph not go through and why?
 Quadrant I, because the slope is negative and the y-intercept is positive
 Quadrant II, because the slope is positive and the y-intercept is negative
 Quadrant III, because the slope is negative and the y-intercept is positive
 Quadrant IV, because the slope is positive and the y-intercept is negative