Question

Find the root of the equation below x^2-6x+12=0

Answer 1

The equation has no real solution.

Explanation:

`\text{The quadratic formula:}\\\\ax^2+bx+c=0\\\\\Delta=b^2+4ac\\\\if\ \Delta<0,\ then\ the\ equation\ has\ no\ solution\\if\ \Delta=0,\ then\ the\ equation\ has\ one\ solution\ x=(-b)/(2a)\\if\ \Delta>0,\ then\ the\ equation\ has\ two\ solutions\ x=(-b\pm\sqrt\Delta)/(2a)\\-----------------------------`

`\text{We have the equation:}\\\\x^2-6x+12=0\\\\a=1,\ b=-6,\ c=12\\\\\Delta=(-6)^2-4(1)(12)=36-48=-12<0`