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What is the Integral of 10^ln x dx?

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User Sbaar
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1 Answer

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10^(\ln x)=e^{\ln 10^(\ln x)}=e^(\ln x\cdot\ln 10)=(e^(\ln x))^(\ln10)=x^(\ln10)

So we have


\displaystyle\int10^(\ln x)\,\mathrm dx=\int x^(\ln10)\,\mathrm dx}=(x^(1+\ln10))/(1+\ln10)+C

which, as the above manipulation showed, is equivalent to


(x10^(\ln x))/(1+\ln10)+C

answered
User Chunky Chunk
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