Question

Please help I’m disliking algebra 2!!!

Answer 1

`C.\:h(x)=2(x-9)(x+3)^2`

Explanation:

If the polynomial function has zeros at 9 with multiplicity 1, then
`(x-9)` is a factor of the polynomial.

Also if the polynomial function has a zero at
`-3` with a multiplicity of 2, then

`(x+3)^2` is another factor of the polynomial.

The polynomial function can therefore be written as;

`h(x)=a(x-9)(x+3)^2`

But the given polynomial has an
`a` value of 2, hence the required polynomial is

`h(x)=2(x-9)(x+3)^2`