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1 vote
Find the sine and cosine of the angle whose terminal side passes through (-7,2)

asked
User JoeCamel
by
9.2k points

1 Answer

4 votes

Answer:

The sine = 0.2724 and the cosine = -0.9615 to 4 decimal places.

Explanation:

The point (-7,2) is in the second quadrant .

The sine is positive and the cosine is negative,.

The hypotenuse of the triangle in the second quadrant = √((-7)^2 + 2^2)

= √53 ( by Pythagoras), the opposite side = 2 and the adjacent side = -7.

So the sine of the angle is 2 /√53 and the cosine is -7/√53.

or 0.2724 and -0.9615 to 4 decimal places.

answered
User Neolith
by
8.5k points

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