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Fill in the blank to make the expression a perfect square.
v^2 + 8v +

1 Answer

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Answer:


\large\boxed{v^2+8v+4^2=v^2+8v+16=(v+4)^2}

Explanation:

Use


(a+b)^2=a^2+2ab+b^2


v^2+8v=v^2+2(v)(4)\qquad\text{add}\ 4^2\ \text{to both sides}\\\\v^2+8v+4^2=v^2+2(v)(4)+4^2\\\\v^2+8v+16=v^2+2(v)(4)+4^2

answered
User Upaang Saxena
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