How many milliliters of 6.45M HCl solution should be used to prepare 4.50 L of 0.600M HCl

Question

asked Oct 5, 2020 233k views

1 Answer

ViTUu · Answer 1 · 2020-10-08T12:20:19+0000

Answer: 418.6 mL of stock solution of HCl will be needed to prepare the required amount of solution.

Step-by-step explanation:

To calculate the volume of stock solution required to prepare the HCl solution, we use the following equation:

M_1V_1=M_2V_2

where,

$M_1\text{ and }V_1$ are the molarity and volume of Stock HCl solution

$M_2\text{ and }V_2$ are the molarity and volume of required HCl solution.

We are given:

Conversion factor: 1L = 1000mL

$M_1=6.45M\\V_1=?mL\\M_2=0.6M\\V_2=4.5L=4500mL$

Putting values in above equation, we get:

$6.45* V_1=0.6* 4500\\\\V_1=418.6mL$

Hence, 418.6 mL of stock solution of HCl will be needed to prepare the required amount of solution.