Question

G(x)=2x-1

h(x)=1-g(x)

The functions of g and h are defined above. What is the value of h(0)?

Answer 1

g(x)= 2x-1

so h(x)=1-(2x-1)

=1-2x+1

=2-2x

h(0)=2-2*0

=2-0

=2

Answer 2

h(0) = 2

Explanation:

given h(x) = 1 - g(x), then

h(x) = 1 - (2x - 1) = 1 - 2x + 1 = 2 - 2x

h(0) = 2 - 0 = 2