Question

the diagram shows a right angled triangle. its hypotenuese is (x+4) cm while tge lengths of the otger two sides are x cm and (2x-y) cm respectively. If the perimeter of the triangle is 24 cm, find the value of x and of y with the condition x> y​

Answer 1

sum of all sides of triangle =perimeter of it

x+4+x+2x-y=24
4x-y=20
y=4x-20

H^2=p^2+b^2
(x+4)^2=x^2+(-2x+20)^2
From here you can calculate value of x and y
x^2+16+8x=5x^2-80x+400
4x^2-88x+384
=x^2-22x+96
you use quadratic formula to calculate x and y
Remember greatest value should be x and smallest should be y as the conditions given above