Question

What the vertex and AOS if the equation is y=(x-2)^2-2

Answer 1

See below.

Explanation:

For y = a(x - b)^2 + c , the vertex is at (b, c) and the axis of symmetry is x = b.

So for y = (x-2)^2 - 2,

the vertex is (2, -2) and the axis of symmetry is x = 2.