Question

line passes through the point (-3,-4) and its y-intercept is (o, -9). What is the equation of the line that is parallel to the first line and passes through the point (3, -7)?

Answer 1

`y=-(5)/(3)x-2`

Explanation:

The first line has a slope of -5/3 found using the points in the slope formula.

`m=(y_2-y_1)/(x_2-x_1) =(-9--4)/(0--3)=(-9+4)/(0+3)=(-5)/(3)`

Parallel lines have the same slope. So -5/3 is the slope of the second line. Write its equation using the point slope form
`y-y_1=m(x-x_1)`.

`y--7=-(5)/(3)(x-3)\\y+7 = -(5)/(3)(x-3)\\y=-(5)/(3)x + 5 -7\\y=-(5)/(3)x-2`