Question

Pls help on this one?

Answer 1

`\large\boxed{D.\ x+4}`

Explanation:

`(x^2-16)/(x-4)\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=(x^2-4^2)/(x-4)=((x-4)(x+4))/(x-4)\\\\\text{canceled}\ (x-4)\\\\=(x+4)/(1)=x+4`