Question

I've been stuck on this for a while so any help would be great.

Answer 1

Value of
`x = (19)/(2)`

Explanation:

Given: Two triangles ΔABC and ΔAED are congruent.

Sides AE= 3 EC= 5 and AD = (x-2), BD = (x+3)

To find: the value of x.

Solution: Since given two triangles ΔABC and ΔAED are congruent.

Therefore sides
`(3)/(8) = ((x-2))/((x-2)+(x+3)) = (x-2)/(2x+1)`

By cross multiplication 8(x-2) = 3(2x+1)

8x - 16 = 6x + 3

8x -6x = 16 + 3

2x = 19

x =
`(19)/(2)`

So the value of x = 19/2.