How many possible combinations would there be for a-z, with a 4 character limit. I tried 4^26, but that was not a correct answer. How would I go about correctly solving this?

Question

asked Apr 2, 2020 15.2k views

1 Answer

Megamit · Answer 1 · 2020-04-08T03:01:29+0000

Hello from MrBillDoesMath!

Answer:

26^4

Discussion:

Each of the 4 characters belong to the 26-character set {a.b...,z}. Therefore the number of combinations is 26^4 ( = 456,976)

Thank you,

MrB