Question

A reaction is expected to produce 28.3 moles of hydrogen gas. If the hydrogen is collected at 297 K and 1.08 atm, what is the volume?

Answer 1

639 L H^2

Step-by-step explanation:

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Answer 2

Volume = nRT/P

n = number of particles (moles)

R = universal gas constant (0.0821)

T = temperature of gas (Kelvin)

P = pressure (atm)

The equation can be set up as (28.3moles)(297K)(0.0821)/1.08atm, which equals 639 L of hydrogen gas.