Question

Triangle AOC intersects a circle with center O. side AO is 10 inches and the diameter of the circle is 12 inches. What is the length of BC

Answer 1

it's 15

Explanation:

Answer 2

`AC=8inches`

Explanation:

It is given that triangle AOC intersects a circle with center O, side AO is 10 inches and the diameter of the circle is 12 inches, thus

OC is the radius of the circle and is equal to
`(D)/(2)=(12)/(2)=6 inches`.

Now, From ΔAOC, using the Pythagoras theorem, we get

`(OA)^(2)=(OC)^(2)+(AC)^(2)`

⇒
`(10)^(2)=(6)^2+(AC)^2`

⇒
`100=36+(AC)^2`

⇒
`64=(AC)^2`

⇒
`AC=8inches`