Question

Y=2x-2 and 4x+2y=12. solve the equation PLEASE SHOW WORK​

Answer 1

x = 2 and y = 2 → (2, 2)

Explanation:

`\left\{\begin{array}{ccc}y=2x-2&\text{subtract 2x from both sides}\\4x+2y=12\end{array}\right\\\\\left\{\begin{array}{ccc}-2x+y=-2&\text{multiply both sides by 2}\\4x+2y=12\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}-4x+2y=-4\\4x+2y=12\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad4y=8\qquad\text{divide both sides by 4}\\.\qquad\qquad\boxed{y=2}\\\\\text{Put the value of y to the second equation:}`

`4x+2(2)=12\\4x+4=12\qquad\text{subtract 4 from both sides}\\4x=8\qquad\text{divide both sides by 4}\\\boxed{x=2}`

Answer 2

The solution as an ordered pair is (x,y) = (2,2)

x = 2 and y = 2 pair up together.

===============================

Work Shown:

4x+2y = 12

4x+2( y ) = 12

4x+2( 2x-2 ) = 12 ... replace y with 2x-2

4x+2( 2x ) + 2( -2 ) = 12 ... distribution rule

4x+4x-4 = 12

8x-4 = 12

8x-4+4 = 12+4 ... add 4 to both sides

8x = 16

8x/8 = 16/8 ... divide both sides by 8

x = 2 is the first part of the answer

Use x = 2 to find y

y = 2x-2

y = 2(2)-2 ... replace x with 2

y = 4-2

y = 2 is the second part of the answer