asked 217k views
4 votes

\binom{ \sqrt[6]{s} * \sqrt{ {s}^(9) } } { \sqrt{16 {s}^(18) } }

sixth root of s
times
square root of s to the 9th
divided by
square root of 16 times s to the 18th

asked
User Lillq
by
8.0k points

1 Answer

5 votes

Quick note: the
\dbinom xy expression you used is misleading and not the same as
\frac xy.

The notations
\sqrt[n]s and
s^(1/n) are equivalent in this context:


\frac{\sqrt[6]s√(s^9)}{\sqrt{16s^(18)}}=(s^(1/6)s^(9/2))/(√(16)s^(18/2))=(s^(1/6+9/2))/(4s^9)=(s^(14/3))/(4s^9)=\frac{s^(-13/3)}4=\frac4{s^(13/3)}=\frac4{\sqrt[3]{s^(13)}}

answered
User Bhavinb
by
8.3k points
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