Question

For what value of y does 125 =
(1/25)^y-1

Answer 1

`y = -(1)/(2)`

Explanation:

I assume that y - 1 is an exponent, and the equation is

`125 = ((1)/(25))^(y - 1)`

`5^3 = (5^(-2))^(y - 1)`

`5^3 = 5^(-2y + 2)`

`-2y + 2 = 3`

`-2y = 1`

`y = -(1)/(2)`