Question

?$5400 is? invested, part of it at 11?% and part of it at 8?%. For a certain? year, the total yield is ?$522.00. How much was invested at each? rate?

Answer 1

• $3000 at 11%
• $2400 at 8%

Explanation:

Let x represent the amount invested at 11%. Then (5400-x) is the amount invested at 8%. The total interest earned is the sum of the interest amounts earned on each investment. Each of those is the product of the interest rate and the amount invested.

(5400-x)·8% + x·11% = 522

432 +0.03x = 522 . . . . . . . . simplify

.03x = 90 . . . . . . . . . . . . . . . subtract 432

90/.03 = x = 3000 . . . . . . . . divide by the coefficient of x

$3000 is invested at 11%; $2400 is invested at 8%.