Question

Points j and k plotted on the coordinate grid are two vertices of rectangle jklm rectangle jklm has an area of 7 square units point j is located at 2,1 and point k is located at -5,1 each vertex of the rectangle is located at a point that has integer coordinates. What is the perimeter of rectangle jklm? (Need answer asap)

Answer 1

c

Explanation:

Answer 2

Perimeter = 16 square units

Explanation:

Since, J(2,1) and K(-5,1) are two adjacent vertices of the rectangle JKLM so the distance between these two points can give us the corresponding length or breadth of the rectangle JKLM.

Let JK be the length of rectangle JKLM

So, to find distance between the points J and K :

`Length = √((x_2-x_1)^2+(y_2-y_1)^2)\\\\\implies Length = √((-5-2)^2+(1-1)^2)\\\\\implies Length = √(7^2+0)\\\\\bf\implies Length=7\textbf{ units}`

Now, Area of rectangle = Length × Breadth

⇒ 7 = 7 × Breadth

⇒ Breadth = 1 unit

Now, Perimeter of rectangle is given by = 2·( Length + Breadth)

⇒ Perimeter = 2·( 7 + 1)

⇒ Perimeter = 2 × 8

⇒ Perimeter = 16 square units