Question

A punter on Westview High School's football team kicks a ball straight up from 5 feet above the ground with an initial upward velocity of 45 feet per second. The height of the ball above ground after t seconds is given by the equation h = –16t2 + 45t + 5, where h is the height of the ball in feet and t is the time in seconds since the punt. What is the maximum height of the ball, to the nearest foot?

Answer 1

Answer: A. 37 feet

Explanation:

1. You can find the x value of the vertex of the parabola as following:

`x=-(b)/(2a)`

2. Substitute values:

a=-16

b=45

`x=-(45)/(2(-16)`

`x=1.40`

3. Substitute the vaue obtained into the equation given in the problem. Therefore, you obtain the following result:

`h=-16(1.40)^(2)+45(1.40)+5\\h=36.64`

4. To the nearest foot:

`h=37ft`