The sum of the roots of x^2+6x-55=0

Question

asked Sep 9, 2020 234k views

2 Answers

Proseosoc · Answer 1 · 2020-09-15T05:25:53+0000

Answer:

The sum of the roots is

Explanation:

we know that

The formula to solve a quadratic equation of the form
ax^(2) +bx+c=0 is equal to

$x=\frac{-b(+/-)\sqrt{b^(2)-4ac}} {2a}$

in this problem we have

x^(2) +6x-55=0

so

$a=1\\b=6\\c=-55$

substitute in the formula

$x=\frac{-6(+/-)\sqrt{6^(2)-4(1)(-55)}} {2(1)}$

$x=\frac{-6(+/-)√(256)} {2}$

$x=\frac{-6(+/-)16} {2}$

$x1=\frac{-6(+)16} {2}=5$

$x2=\frac{-6(-)16} {2}=-11$

The roots are
5,-11

Find the sum of the roots

5+(-11)=-6