Drag an expression or phrase to each box to complete the proof.

Question

asked Jul 12, 2020 121k views

2 Answers

Pooky · Answer 1 · 2020-07-14T15:32:53+0000

<BAD ≅ <CFD Alternate interior angles theorem

<ADB ≅ <CDF Vertical angles are congruent

Δ ADB ≈ Δ FDC Angle angle similarity postulate

Unreality · Answer 2 · 2020-07-16T02:22:07+0000

Answer:

a)
$\angle BAD = \angle CFD$

Since we are given that AB || CF

So,
$\angle BAD = \angle CFD$ (Alternate interior angles)

b)
$\angle ADB = \angle CDF$

Since they are vertical angles , So, they are congruent

c)ΔADB ≈ΔFDC

$\angle ADB = \angle CDF$ (vertical angles)

$\angle BAD = \angle CFD$ (Alternate interior angles)

$\angle ABD = \angle FCD$ (Alternate interior angles)

So, ΔADB ≈ΔFDC (By angle angle similarity postulate )