1kg of water needs to recieve 4200J of energy to go from 90 degrees to 91 degrees. What is the specific heat capacity of water? What are the units?

Question

asked Mar 14, 2020 142k views

1 Answer

Fabian Bigler · Answer 1 · 2020-03-17T16:55:37+0000

For the change in temperature of water we require heat which is given by formula

$Q = m s \Delta T$

here we will have

Q = 4200 J

m = 1 kg

initial temperature = 90 degree C

final temperature = 91 degree C

now we will have

$\Delta T = 91 - 90 = 1 degree C$

from above equation we will have

4200 J = (1 kg) s (91 - 90)^0C

now we will have

$s = frac{4200 J}{(1 kg)(1 ^0C)$

s = 4200 J/(kg ^0C)