Question

What is an equation of the line that is perpendicular to y=-3/4x+6 and passes through the point (3,9)

Answer 1

`y=(4)/(3)x+5`

Explanation:

The line y= -3/4+6 in the comments has slope -3/4. A perpendicular line will have the negative reciprocal of -3/4. It's 4/3.

To write the equation, substitute 4/3 and the point (3,9) into

`y-y_1 = m(x-x_1)`

`y-9=(4)/(3)(x-3)\\\\y-9=(4)/(3)x -(4*3)/(3)\\\\y-9=(4)/(3)x-4\\\\y=(4)/(3)x+5`