Question

Multiply Conjugates Using the Product of Conjugates Pattern

In the following exercises, multiply each pair of conjugates using the Product of Conjugates Pattern
334. (9c − 2d)(9c + 2d)

Answer 1

The product is the difference of squares is
`$$(9c-2d)(9c+2d)=81{{c}^2}-4{{d}^2}$$`

Explanation:

Explanation

• The given expression is (9c-2d)(9c+2d).

• We have to multiply the given expression.

• Square the first term 9c. Square the last term 2d.

`$$\begin{aligned}&(9 c-2 d)(9 c+2 d)=(9 c)^(2)-(2 d)^(2) \\&(9 c-2 d)(9 c+2 d)=81 c^(2)-4 d^(2)\end{aligned}$$`