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A fireman is standing 30 m directly west of a burning building. His ladder reaches 50m up the side of the building. What is the angle of elevation to the closest degree of his ladder?

asked
User Murtaza
by
7.6k points

1 Answer

5 votes

Answer:

As per the statement:

You can see the diagram as shown below.

Distance of fireman stands away from the building = 30 m

Length of the ladder = 50 m

Using Cosine ratio:


\cos \theta = \frac{\text{Adjacent side}}{\text{Hypotenuse side}} ....[1]

From the diagram:

Adjacent side = 30 m

Hypotenuse side = 50 m

Substitute these values in [1] to solve for angle of elevation(
\theta)


\cos \theta = (30)/(50) = 0.6

or


\theta = \cos^(-1) (0.6)

Simplify:


\theta = 53.13^(\circ)

Therefore, the angle of elevation to the closest degree of the ladder is 51.13 degree

A fireman is standing 30 m directly west of a burning building. His ladder reaches-example-1
answered
User Serge Pedroza
by
8.1k points
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