asked 69.4k views
5 votes
In a large single-elimination basketball tournament, the first round of play begins with 64 teams. In each successive round, the number of teams remaining in the tournament is reduced by half. This relationship can be described by the following exponential function.

asked
User Pork
by
8.4k points

2 Answers

2 votes

Answer:

f(n)=f(n-1)÷2

Explanation:


answered
User Crowlix
by
8.1k points
4 votes

Answer:


T_(n)=64((1)/(2))^(n-1) defines the relationship.

Explanation:

In a large single elimination basketball tournament, the first round of the play begins with 64 teams.

In each successive round, the number of teams remaining in the tournament is reduced by half.

So the sequence formed will be 64, 32, 16, 8........

Now we have to find the relationship.

In the sequence there is a common ratio of
(1)/(2) in each successive term

r =
\frac{\text{2nd term}}{\text{1st term}}=(64)/(32)=2

Since explicit formula of an exponential sequence is


T_(n)=a(r)^(n-1)


T_(n)=64((1)/(2))^(n-1)

Therefore, equation representing the relationship will be


T_(n)=64((1)/(2))^(n-1)

answered
User Mmfrgmpds
by
8.6k points
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