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Which would prove that ABC ~ XYZ? check all that apply

Which would prove that ABC ~ XYZ? check all that apply-example-1
asked
User Michael
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2 Answers

4 votes

Answer: A and C

Explanation:

Got it right on edg

answered
User WPrecht
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8.6k points
4 votes

Answer:

Option: A and C are correct.

Explanation:

For ΔABC~ΔXYZ.

option: A


(BA)/(YX)=(BC)/(YZ)=(AC)/(XZ)

if this property is satisfied than the SSS similarity theorem will hold and the two triangles will be similar.

( since Side-Side-Side (SSS) Similarity Theorem - If the lengths of the

corresponding sides of two triangles are proportional, then the

triangles must be similar )

Option: C


(AC)/(XZ)=(BA)/(YX) and ∠A≅∠X.

in this case the SAS similarity will hold true and

hence ΔABC~ΔXYZ.

( since Side-Angle-Side (SAS) Similarity Theorem - If an angle of one

triangle is congruent to an angle of a second triangle and the lengths of

the sides including these angles are proportional, then the triangles

must be similar ).





answered
User Ishaq Khan
by
7.9k points

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