Question

The athletic department at pi high is planning circular track it is 400 m long. The area inside will be planted with sod. How much sod do I need?

Answer 1

15,400tds^2

Explanation:

440 = Pi x 2r (Diameter = 2 x radius)

Radius = 440/2 x Pi

Area of circle = Pi x (440/2 x Pi)^2

Area of circle = 15406.i9 yds^2

= 15,400 yds^2 (nearest 100 yd^2)