Question

A frog leaps from flat ground at 6.32 m/s

at a 36.3 angle. What maximum height
does it reach?
(Unit = m)

Answer 1

.714

Step-by-step explanation:

Answer 2

.714 m

Step-by-step explanation:

The VERTICAL component is all we are interested in for this Q

Vertical velocity = 6.32 m/s sin 36.3° = 3.742 m/s

Vertical displacement = vo t - 1/2 at^2

= -1/2 at^2 + vo t

max occurs at - b/2a = -3.742/ (2(-1/2(9.81)) = .3814 sec

then vot-1/2 at^2 =

3.742 (.3814) - 1/2 ( 9.81)(.3814^2) = .714 m