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What are the zeros of the function f(x)=x^4-4x^2-5

1 Answer

7 votes

Answer:


x =√(5) ,-√(5) ,-i,i

Step-by-step solution:


0=x^4-4x^2-5
u = x^2

0 = u^2-4u-5

0 = (u -5)(u+1)

u = 5
u=-1

x^2 =5
x^2 = -1

x= +-√(5)
x = +-i

answered
User Neilakapete
by
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