Question

Trapezoid ABCD has vertices A (2, 4), B (5, 4), C (7, 1), and D (0, 1). What are the lengths of the sides AD and BC?

Answer 1

√13 ≈ 3.61

Explanation:

The distance formula is applicable.

d = √((x2-x1)² +(y2-y1)²)

AD = √((0-2)² +(1-4)²) = √(4+9) = √13

AD ≈ 3.605513 ≈ 3.61

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The trapezoid is isosceles, so AD and BC are the same length, 3.61.