Question

A goblet contains 333 red balls, 222 green balls, and 666 blue balls. if we choose a ball, then another ball without putting the first one back in the goblet, what is the probability that the first ball will be red and the second will be blue?

Answer 1

Explanation:

4

89

69849

55

Answer 2

`(9)/(55)`

Explanation:

A goblet contains 3 red balls, 2 green balls and 6 blue balls.

Total balls = 3 + 2 + 6 = 11 balls

we choose a ball and then another ball without putting the first one back.

The probability that the first ball will be red =
`P_(1)` =
`(3)/(11)`

Second event is done without replacing the first ball so total ball will be 10

The probability that the second ball will be blue =
`P_(2)` =
`(6)/(10)` =
`(3)/(5)`

P =
`(3)/(11)` ×
`(3)/(5)` =
`(9)/(55)`

The probability that the first ball will be red and the second ball will be blue is
`(9)/(55)`