A 0.100-kllogram apple falls "am a height M150 metals to 1 00 meters, Ignoring frIcﬁona| effeds, what is the kmeﬂc energy loe apple at lhls height?

Question

asked May 24, 2020 35.0k views

1 Answer

Jasonhudgins · Answer 1 · 2020-05-28T10:24:03+0000

Answer: The kinetic energy of an apple at 100 m of height while falling is 49 J.

Step-by-step explanation:

Mass of the apple = 0.100 kg

Height at that instant when apple was at verge of falling = 150 m

The sum of the potential energy and kinetic remains constant.

Sum of P.E and K.E energy at height if 150 m

P.E+K.E=mgh+(1)/(2)mv^2

Kinetic energy is zero at initial position

=0.100 kg* 9.8 m/s^2* 150 m=147 J+0 J=147 J

Sum of P.E and K.E at height if 100 m

P.E+K.E=mgh'+(1)/(2)mv^2

Kinetic energy is not zero during falling of an apple

=0.100 kg* 9.8 m/s^2* 100 m=98 J+K.E.=147 J

K.E = 147 J - 98 J= 49 J

The kinetic energy of an apple at 100 m of height while falling is 49 J.