Question

Someone please help me with this

Answer 1

BE = 3 in; EF = 2 in; FC = 3 in

Explanation:

∠EAD ≅ ∠AEB ≅ ∠EAB so ΔABE is isosceles and AB ≅ BE = 3 in.

Likewise, ∠FDC ≅ ∠FDA ≅ ∠DFC, so ΔDCF is isosceles and AB ≅ BC ≅ FC = 3 in.

Then EF = 8 in - 3in - 3 in = 2 in