Question

What is the equation, in point-slope form, of the line that is parallel to the given line and passes through the point (−3, 1)?

y – 1=(x + 3)
y – 1=(x + 3)
y – 1= (x + 3)
y – 1= (x + 3)

Answer 1

Answer: y - 1= 3/2 (x + 3)

Explanation:

Answer 2

The required equation is
`y-1=(3)/(2)(x+3)`

Explanation:

The equation of given line is

`y-2=(2+4)/(2+2)(x-2)`

`y-2=(3)/(2)(x-2)`

`y=(3)/(2)x-1`

The slope of the given equation is
`(3)/(2)`

As we know the slope of parallel line is equal.

Thus, The slope of required line is
`(3)/(2)`

Passing point: (-3,1)

Using point slope formula:

`y-y_1=m(x-x_1)`

`y-1=(3)/(2)(x+3)`

Hence, The required equation is
`y-1=(3)/(2)(x+3)`